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[SR-11998] can't declare implicitly unwrapped optional of type with inferred generic parameters #54432

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marcrasi mannequin opened this issue Jan 7, 2020 · 3 comments
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[SR-11998] can't declare implicitly unwrapped optional of type with inferred generic parameters #54432

marcrasi mannequin opened this issue Jan 7, 2020 · 3 comments
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@DougGregor
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bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself type checker Area → compiler: Semantic analysis

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@marcrasi
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marcrasi mannequin commented Jan 7, 2020

Previous ID SR-11998
Radar rdar://problem/58455441
Original Reporter @marcrasi
Type Bug
Status Resolved
Resolution Done
Additional Detail from JIRA
Votes 0
Component/s Compiler
Labels Bug, TypeChecker
Assignee @DougGregor
Priority Medium

md5: c1e36f49a5241c93c0abf6cec90bfad7

Issue Description:

struct Generic<T> {}
let _: Generic! = Generic<Int>()

On Ubuntu 18.04 development snapshot 2020-01-03, this compiles without error.
On Ubuntu 18.04 development snapshot 2020-01-04 and later, this produces an error:

workspace/iuo.swift:2:8: error: using '!' is not allowed here; perhaps '?' was intended?
let _: Generic! = Generic<Int>()

If you do `let _: Generic<Int>! = Generic<Int>()` instead, then there is no error.
@beccadax
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beccadax commented Jan 9, 2020

@swift-ci create

@beccadax
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This reproduces on macOS, too. I think this is a regression caused by #29005.

(Thank you for tracing it down to a specific snapshot! That probably saved me an hour of work.)

@DougGregor
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Fixed by #30496

@swift-ci swift-ci transferred this issue from apple/swift-issues Apr 25, 2022
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@DougGregor DougGregor

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bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself type checker Area → compiler: Semantic analysis
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@beccadax @DougGregor