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[SR-2143] Passing IUO type as parameter of Any.Type does not convert it to Optional type #44751

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swift-ci opened this issue Jul 21, 2016 · 3 comments
Open

[SR-2143] Passing IUO type as parameter of Any.Type does not convert it to Optional type #44751

swift-ci opened this issue Jul 21, 2016 · 3 comments
Labels
bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself standard library Area: Standard library umbrella

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@swift-ci
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Previous ID SR-2143
Radar None
Original Reporter ilyapuchka (JIRA User)
Type Bug
Additional Detail from JIRA
Votes 0
Component/s Compiler, Standard Library
Labels Bug
Assignee None
Priority Medium

md5: 5e7e9e54137bdb614b454149b904aa8f

Issue Description:

When IUO type is passed as a parameter of type Any.Type it is not converted to Optional type.

Example:

    let opt = (Int?).self
    let iuo = (Int!).self
    
    func printType(type: Any.Type) {
      print(type)
    }
    
    printType(type: opt) //Optional<Int>
    printType(type: iuo) //ImplicitlyUnwrappedOptional<Int>
@belkadan
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Yeah, we just haven't finished implementing SE-0054 yet.

@swift-ci
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Comment by Jin Wang (JIRA)

Any updates?

@swift-ci
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swift-ci commented Oct 7, 2016

Comment by Ilya Puchka (JIRA)

Still happens in Xcode 8 GM

@swift-ci swift-ci transferred this issue from apple/swift-issues Apr 25, 2022
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bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself standard library Area: Standard library umbrella
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@belkadan @swift-ci