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[SR-3561] can't use initializer with default argument to define a lazy var #46149

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swift-ci opened this issue Jan 6, 2017 · 1 comment
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[SR-3561] can't use initializer with default argument to define a lazy var #46149

swift-ci opened this issue Jan 6, 2017 · 1 comment
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bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself

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@swift-ci
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swift-ci commented Jan 6, 2017

Previous ID SR-3561
Radar None
Original Reporter cezarywojcik (JIRA User)
Type Bug
Status Resolved
Resolution Duplicate
Additional Detail from JIRA
Votes 0
Component/s Compiler
Labels Bug
Assignee None
Priority Medium

md5: 95bdd554da53d58e97b34e74bf85bf99

cloned to:

  • SR-3809 errors out on the addOperation() for OperationQueue

duplicates:

  • SR-2616 'lazy' keyword results in "Type of expression is ambiguous without more context"

Issue Description:

Sample Code:

class MyClass {

    init(value: String = "ohno") {
        print(value)
    }

}

class MyOtherClass {

    lazy var test = MyClass()

}

let _ = MyOtherClass()

The error we get:

Playground execution failed: error: MyPlayground.playground:5:21: error: type of expression is ambiguous without more context
    lazy var test = MyClass()
                    ^~~~~~~~~

The code works fine if we remove the lazy.
@belkadan
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Consolidating.

@swift-ci swift-ci transferred this issue from apple/swift-issues Apr 25, 2022
This issue was closed.
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bug A deviation from expected or documented behavior. Also: expected but undesirable behavior. compiler The Swift compiler in itself
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@belkadan @swift-ci