Comment by aaron crespo (JIRA)

you can disambiguate with `Swift.type(of: )`

Additionally the code sample here:

https://developer.apple.com/documentation/swift/2885064-type?changes=latest_minor

fails with a similar issue

This does seem to have worked in Xcode 8.3.3.

@swift-ci create

This is correct. type(of:) is just a function in Swift 4. It doesn't do anything special. That means it can be shadowed like any other top-level function. (There are existing bugs for improving that experience.)

Comment by aaron crespo (JIRA)

Note that I used Int just as a means to reduce the test case. It happens on all types.

Is it shadowing within the instance if one is a property and one is a function? I thought they were distinct?

With

let list = [1,2,3,45,5]
let types1 = list.map { $0.type } // works
let types2 = list.map(Int.type) // doesn't work as expected member is not a function
let types3 = list.map { $0[keyPath: \Int.type] } // works
let types4 = list.map(type) // doesn't work with different error from types2 reference to Swift.type not implemented.

Compiles with two different errors, if shadowing was happening and was the cause of this wouldnt I expect the same error?